the sum of first n terms of an AP is given by Sn = 2n square + 3n . find the sixteenth term of the AP
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S1 = 2 (1)^2 + 3 (1) = 5
S16 = 2 (16)^2 + 3 (16) = 560
Sn = n/2 (A + L)
S16 = 16/2( 5 + L)
560 = 40 + 8L
520 = 8L
65 = L
16th tern is 65
S16 = 2 (16)^2 + 3 (16) = 560
Sn = n/2 (A + L)
S16 = 16/2( 5 + L)
560 = 40 + 8L
520 = 8L
65 = L
16th tern is 65
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