Question

Prove that diagonals of a rhombus bisect each other at right angles ?

Answer 1

consider the rhombus ABCD
AB=BC=CD=DA (adjecent sides are equal)
in triangleAOD and triangle COD
OA=OC (diagonals of parallogram bisect each other )
OD is common
AD=CD(PROVED ABOVE)
TRIANGLE AOD congurent to triangleCOD(SSS)
ANGLE AOD = ANGLE COD (CPCT)
ANGLE AOD + ANGLE COD = 180 (L P)
2 ANGLE AOD = 180
ANGLE AOD = 90


HENCE PROVED

Answer 2

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