Question

Q 11...and Q12 plzzz mention the ques no

Answer 1

HOPE THIS WILL HELP U

Answer 2

HELLO DEAR,

------(1)

Given that :-

raidus of Circle =21 meter

angle theta=90°

area of graze =
$\frac{ \alpha }{360} \times \pi {r}^{2} \\ = > \frac{90}{360} \times \frac{22}{7} \times 21 \times 21 \\ = > \frac{1}{4} \times 22 \times 3 \times 21 \\ = > 33 \times 10.5 =346.5 {m}^{2}$

----(2)

Two concentric circles whose radius are 14cm and 7cm

area of space between them=

[(area of CIRCLE of radius 14cm) - area of Circle of radius 7cm) ]

=>
$\pi( {14})^{2} - \pi ({7})^{2} \\ > \pi( {14}^{2} - {7}^{2} ) \\ = > \pi(196 - 49) \\ = > \frac{22}{7} (147) \\ = > 22 \times 21 = 462c {m}^{2}$
I HOPE ITS HELP YOU DEAR,
THANKS