Math, asked by jeeavika, 10 months ago

Rekha borrows . 12,500 at 12% per annum for 3 years at simple interest and Radha borrows the same amount for the same time period at 10% p.a., compounded annually. Who pays more interest and by how much?

Answers

Answered by suprapti63
1

Step-by-step explanation:

rekha's interest = principal × rate × time ÷100

= 12500×12×3÷100

= 4500

radha's interest = 12500×10×3÷100

=3750

rekha interest - radha interest

= 4500-3750

=750

rekha pays more interest by 750

Answered by SidhantVerma77
3

Answer:

Rekha pays more interest and by ₹2637.5

Step-by-step explanation:

Simple Interest for Rekha,

Simple Interest = p*r*t/100

= 12,500*12*1/100

= 125*12 = 1500

Simple Interest = ₹1500

Compound Interest for Radha,

Interest for the first year = p*r*t/100

= 12500*10*1/100

= 1250

Amount = principal + interest

= 12500 + 1250 = 13750

Principal for the second year = 13750

Interest for the second year = p*r*t/100

= 13750*10*1/100

= 1375

Amount = principal + interest

= 13750 + 1375 = 15125

Principal for the third year = 15125

Interest for the third year = p*r*t/100

= 15125*10*1/100

= 1512.5

Compound Interest = 1250 + 1375 + 1512.5

= ₹4137.5

Radha pay more interest than Rekha and by 4137.5 - 1500 = 2637.5(answer).

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