Question

sin^2(2x-10)+sin^2 30°

Answer 1

Answer:

sin²(2x-10)+1/4

is right answer

Answer 2

$\huge\bold\red{Question:-}$

sin²(2x-10) + sin²30° = 1

$\huge\bold\green{Answer:-}$

sin²(2x-10)°+sin²30° = 1

We have,

$\sin30 = \frac{1}{2}$

${ \sin }^{2} 30 =( \frac{1}{2} ) ^{2} = > \frac{1}{4}$

So,

$\sin^{2} (2x - 10) = 1 - \frac{1}{4} = \frac{3}{4}$

We have,

$\sin60 = \frac{ \sqrt{3} }{2}$

And

$\sin^{2} 60 = ( \frac{ \sqrt{3} }{2} )^{2} = \frac{3}{4}$

So,

sin²(2x-10) = sin²60

So, 2x-10 = 60

2x = 60+10

2x = 70

$x = \frac{70}{2}$

$x = 35$