Question

the adjacent sides of a parallelogram are 15 cm and 10 cm if the distance between the longer side is 6 cm find the distance between the shorter sides​

Answer 1

Bonjour!!

In parallelogram ABCD, AD is between longer side and CM is between shorter side.

AB = CD = 10 cm

BC = AD = 15 cm

AD = 6 cm

CM =? cm

Area of parallelogram = Base × Height

Area = BC × AD

= 15 × 6

= 90 cm^2

Area = AB × CM

90 = 10 × CM

CM = 90/10

CM = 9 cm

Hence, the distance between the shorter side is 9 cm.

Thanks :)

Answer 2

Answer:

$\huge\star\underline{\mathtt\color{aqua}{⫷❥A} \mathfrak\color{yellow}{N~ }\mathfrak\color{blue}{S} \mathbb\color{purple}{W} \mathtt\color{orange}{E} \mathbb\color{red}{R⫸}}\star\:⋆$Let the present age of Rehman =x

3 years ago Rehman’s age =(x–3) years

5 years later Rehman’s age =(x+5) years.

Now, according to the condition,

(x–3)

1

+

(x+5)

1

=

3

1

(x–3)(x+5)

(x+5+x–3)

=

3

1

(x

2

–3x+5x–15)

(2x+2)

=

3

1

x

2

+2x–15=6x+6

x

2

–4x–21=0

(x+3)(x–7)=0

Either,x+3=0 Or, x–7=0

Thus, x=7 or –3; but age cannot be negative.

Hence the present age of Rehman is 7 years.