The diagonal of a quadrilateral shaped field is 24cm and
perpendicular dropped on it from the remaining opposite vertices are 6m and 12m. Find the area of the field.
Answers
Corrrect Question:
The diagonal of a quadrilateral shaped field is 24m and perpendicular dropped on it from the remaining opposite vertices are 6m and 12m. Find the area of the field.
Answer:
_____________________
Given:-
- Diagonal of Quadrilateral = 24m
- Perpendicular dropped from the opposite sides = 6m and 12m
Find:-
- Area of the field
Solution:-
we, know that
➦ Area of Quadrilateral = 1/2 × Diagonal × Sum of perpendicular
➦ Area of Quadrilateral = 1/2 × Diagonal × (h₁ + h₂)
where,
- Diagonal, d₁ = 24m
- h₁ = 6m
- h₂ = 12m
◕ Substituting these values ◕
↬Area of Quadrilateral = 1/2 × d₁ ×(h₁ + h₂)
↬Area of Quadrilateral = 1/2 × 24 ×(6+ 2)
↬Area of Quadrilateral = 1/2 × 24 × 18
↬Area of Quadrilateral = 1/2 × 432
↬Area of Quadrilateral = 432/2
↬Area of Quadrilateral = 216m²
Hence, Area of the given field is 216m²
Correct Question:
The diagonal of a quadrilateral shaped field is 24m and perpendicular dropped on it from the remaining opposite vertices are 6m and 12m. Find the area of the field.
Answer:
_____________________
Given:-
Diagonal of Quadrilateral = 24m
Perpendicular dropped from the opposite sides = 6m and 12m
Find:-
Area of the field
Solution:-
we, know that
➦ Area of Quadrilateral = 1/2 × Diagonal × Sum of perpendicular
➦ Area of Quadrilateral = 1/2 × Diagonal × (h₁ + h₂)
where,
Diagonal, d₁ = 24m
h₁ = 6m
h₂ = 12m
◕ Substituting these values ◕
↬Area of Quadrilateral = 1/2 × d₁ ×(h₁ + h₂)
↬Area of Quadrilateral = 1/2 × 24 ×(6+ 2)
↬Area of Quadrilateral = 1/2 × 24 × 18
↬Area of Quadrilateral = 1/2 × 432
↬Area of Quadrilateral = 432/2
↬Area of Quadrilateral = 216m²