the diameter cof a circle with centre o is perpendicular to chord ab if a b = 12 cm and ce= 3 cm calculate the radius of the circle
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From the figure, we know that CD is the diameter of the circle with centre O which is perpendicular to chord AB
Draw the line OA
It is given that AB=12 cm and CE=3 cm
Consider OA=OC=r cm
It can be written as
OE=(r−3) cm
The perpendicular from the centre of the circle to a chord bisects the chord
We know that
AE=
2
1
×AB
By substituting the values
AE=
2
1
×12
So we get
AE=6 cm
Consider △OEA
By using the Pythagoras theorem
OA
2
=OE
2
+AE
2
By substituting the values
r
2
=(r−3)
2
+6
2
So we get
r
2
=r
2
−6r+9+36
On further calculation
r
2
−r
2
+6r=45
So we get
6r=45
By division
r=
6
45
r=7.5 cm
Therefore, the radius of the circle is 7.5 cm
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