Question

the two zeros of a quadratic polynomial are -4 and -6 find the sum and product of the zeros what is the value of coefficien b​

Answer 1

Step-by-step explanation:

α+β= -4

αβ= -6

Formula to form a quadratic equation using zeros:

x'^2 - (α+β)x + αβ=0

Quadratic equation

x^2 +4x - 6=0

Sum of zeros

α+β = - coefficient of x /coefficient of x^2=-4

Product of zeros

αβ=constant term/coefficient of x^2= -6

Answer 2

Answer :

Sum of zeroes = -(coefficient of x) / coefficient of x^2

-4+(-6) = -b/a

-4-6 = -b/a

-10= -b/a

B/a = 10

Product of zeroes = constant term / coefficient of x^2

-4*-6 = c/a

24 = c/a

So , the value of b = 10

Hope it help you ✌️❣️