There are 104 students in class 10 and 96 students in class 9 in a school. In a house examination the students are to be evenly seated in parallel rows such that no 2 adjacent rows are of the same class. a}. find the max number of parallel rows of each classfor the seating arrangement. b}. Also find the number of students in class 9 and also class 10 in a row c}. What is the objective of the school administration behind such an arrangement.
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There are a total of 200 students (104 and 96).
Both 104 and 96 are divisible by 8, i.e. 104/8 = 13 and 96/8 = 12.
a). Therefore the maximum number of parallel rows would be 12+13 = 25. And, 200/8 = 25.
b). Number of students in each row would be 8.
c). The objective of the school behind such an agreement would be to easily arrange the students in rows such that no adjacent rows have students belonging to one class.
Both 104 and 96 are divisible by 8, i.e. 104/8 = 13 and 96/8 = 12.
a). Therefore the maximum number of parallel rows would be 12+13 = 25. And, 200/8 = 25.
b). Number of students in each row would be 8.
c). The objective of the school behind such an agreement would be to easily arrange the students in rows such that no adjacent rows have students belonging to one class.
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TOTAL STIDENTS=200 AND BOTH ARE DIVISIBLE BY 8
ANS (A)=MAXIMUM NUMBER OF PARALLEL ROW WOULD NE 200/8=25
ANS(B)=NUMBER OF STUDENTS IN EACH ROW OF BOTH CLASSES WOULD BE 8
ANS (C)=TO ARRANGE THE SITTING OF STUDENTS.
HOPE IT HELPS
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