two equal parts pq and rs of a circle with Centre O when produced meet at a point M as shown in the figure.prove that qm=sm
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It is a basic theorm that is to be applied in this question. It is that tangents from an external point to same circle are equal.
So here PM= RM (from same external point M)------------(!)
Also it is given that PQ= RS---------------------(2)
Now subtract equation (2) from (1) we get:-
PM - PQ = RM - RS
QM = SM.
---------------Hence, proved-------------------------
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