Question

What value of y would make AOB a line in Fig. 8.43, if ∠AOC= 4y and ∠BOC =(6y+30)

Answer 1

Answer:

6y+30+4y=180( linear pair)

10y=150

y=15

Answer 2

Concept :  

Linear pair of angles:

If Non-common arms of two adjacent angles form a line, then these angles are called linear pair of angles.

Axiom- 1

If a ray stands on a line, then the sum of two adjacent angles so formed is 180°i.e, the sum of the linear pair is 180°.

 

Given :  AOB a line and ∠AOC = 4y and ∠BOC = (6y + 30).

∠AOC and ∠BOC form a linear pair.

∠AOC + ∠BOC = 180°

6y + 30° + 4y = 180°

6y + 4y = 180° - 30°

10y = 150°

 y = 150°/10

y = 15°

Hence, the value of y is 15°.

HOPE THIS ANSWER WILL HELP YOU…..

 

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