Write the reciprocal of 5 +√2.
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Answer:
1/5+√2 is the reciprocal..
1/5+√2*5-√2/5-√2 (conjugate)
5-√2/25-2
5-√2/23 .
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Given : 5 +√2
The reciprocal of 5 +√2 is 1/5 +√2
To make the denominators free from square roots, we multiply the numerator and denominator by an irrational number. Such a number is called rationalisation factor. The rationalisation factor for 1/(a ± √b) is a -+ √b :
The rationalisation factor for 5 +√2 is 5 - √2 :
1/(5 +√2) = [1 × (5 -√2)] / [(5 +√2) × (5 -√2)]
We know that , (a + b)(a – b) = a² - b² :
= (5 - √2)/ [5² - √2²]
= (5 - √2)/ [25 - 2]
= (5 - √2)/ 23
Hence , the reciprocal of 5 + √2 is 1/5 - √2 = 5 + √2.
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