Question

If the common difference of an AP is 4 , then a30 - a25 is

Answer 1

Answer: 20

Step-by-step explanation:

We know that,

$a_{n} = a + (n-1)d$

⇒ $a_{30} = a + (30-1)d$

⇒$a_{30} = a + 29d$               ......(1)

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⇒ $a_{25} = a + (25-1)d$

⇒$a_{25} = a + 24d$              .....(2)

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⇒ $a_{30} - a_{25} = (1) - (2)$

⇒$(a + 29d) - (a + 24d)$

⇒$a + 29d - a - 24d$

⇒$5d = 5(4) = 20$

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Answer 2

Answer:

We know that,

a_{n} = a + (n-1)dan=a+(n−1)d

⇒ a_{30} = a + (30-1)da30=a+(30−1)d

⇒a_{30} = a + 29da30=a+29d               ......(1)

⇒ a_{25} = a + (25-1)da25=a+(25−1)d

⇒a_{25} = a + 24da25=a+24d              .....(2)

⇒ a_{30} - a_{25} = (1) - (2)a30−a25=(1)−(2)

⇒(a + 29d) - (a + 24d)(a+29d)−(a+24d)

⇒a + 29d - a - 24da+29d−a−24d

⇒5d = 5(4) = 205d=5(4)=20